.048-25x+3000x^2=0

Solution for .048-25x+3000x^2=0 equation:

.048-25x+3000x^2=0

We add all the numbers together, and all the variables

3000x^2-25x+0.048=0

a = 3000; b = -25; c = +0.048;
Δ = b2-4ac
Δ = -252-4·3000·0.048
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*3000}=\frac{18}{6000}
=3/1000
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*3000}=\frac{32}{6000}
=2/375
$